• Peter Posted: 6/17/2009 12:53pm PDT

    I live in NY and yes, people are aggressive. I find it strange how people focus on the reactive part of this equation (road rage) rather than the initial idiotic incidents that trigger it. I'm all for driver continuing education classes and re-certification tests to maintain one's driving privilege -- even as a NYer.
    ps - my reCaptch words included derange -- coincidence?

  • Ben Posted: 6/17/2009 10:33am PDT

    According to an insurance company survey, New York has the most dangerous drivers in the country. So New York not only has the angriest drivers, they have the worst drivers. It would be a nightmare that I wouldn't be able to wake up from if I had to drive with New York and New Jersey in the snow.

  • whodat Posted: 6/16/2009 1:58pm PDT

    I live in southern Florida,Palm Beach County..I have to say New Yorkers Are the worst.most pig headed drivers if there ever was.P>L>O =pushy,loud,obnoxious New Yorkers...

  • Esley Posted: 6/16/2009 12:22pm PDT

    I've only heard stories about New York and Boston from my DH and this report would seem to confirm.
    As far as the most polite cities, surely the story must mean Portland, Maine because I live in Portland, OR and most definitely do NOT concur if they meant OR.
    Now if you go North beyond Vancouver, WA they are so polite as to be a hazard most of the time.

  • John Voelcker Posted: 6/16/2009 9:19am PDT

    Road rage, perhaps ... but for sheer dangerous driving, NYC is paradise compared to Boston.
    I suspect lockjaw New Englanders repress all that rage that we New Yorkers take out in a healthy, constructive way. Instead, their fury comes out in terrifying and oblivious driving.
    That clapped-out 1984 Volvo wagon cutting across three lanes of traffic to skid around the rotary in front of the box van? Driven by a lovely upright Boston Brahmin lady who volunteers at the local library.
    Gimme New York any day. Now get your f&*%ing car outta my g0dd@mn way before I shove it up your M0&%3rf*@$1ng a$$.